In the fission of 
by a thermal neutron, two fission fragments of equal masses and sizes are produced and 4 neutrons are emitted. Find the force between the two fission at the moment they are produced. Given R 0 = 1.1 fermi.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
Sol. Total mass number of 
+ neutron (thermal) = 239 + 1 = 240. Since 4 neutrons are produced, the mass number of each fragment = 
= 118. The atomic number of each fragment = 94/2 = 47. Therefore, charge of each fragment is
q = 47 × 1.6 × 10 –19 = 7.52 × 10 –18 C.
The radius of each nucleus of the fragment is
R = R 0 1/3 = 1.1 × 10
–15 × (118) 1/3 (As 1 fermi = 10
–15 cm)
= 5.395 × 10 –15 m.
Distance between the centers of the fragments at the moment they are produced is
r = 2 × 5.395 × 10 –15 = 10.79 × 10 –15 m.
The electrostatic force between them is,
F = 
. 
= 9 ×10 9 
= 4.37 × 10 3 N.
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